(2x+7)^1/2-x=1

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Solution for (2x+7)^1/2-x=1 equation: 


x in (-oo:+oo)

((2*x+7)^1)/2-x = 1 // - 1

((2*x+7)^1)/2-x-1 = 0

(2*x+7)/2-x-1 = 0

(2*x+7)/2+(2*(-x))/2+(-1*2)/2 = 0

2*x+2*(-x)-1*2+7 = 0

7-2 = 0

5 = 0

5/2 = 0

5/2 = 0 // * 2

5 = 0

x belongs to the empty set

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